## Hypothesis test conducted by our Gretl homework help experts

status | ||||

Frequency | Percent | |||

Employed | 59 | 25.5 | ||

Retired | 172 | 74.5 | ||

Total | 231 | 100.0 |

**Gretl homework help**experts give the sampling error as: For p

_{employed}

_{}

At a 5% level of significance,the z tab is 1.96. Therefore, Z calc (7.45)>Ztab(1.96). In our **Gretl homework solution, **we reject the null hypothesis and conclude that the proportion is significantly different

**Measures of central tendency covered by our Gretl experts**

Fitness | social | enjoy | medical | |||||

frequency | percent | frequency | percent | frequency | percent | Frequency | percent | |

1 | 5 | 2.2 | 49 | 21.2 | 10 | 4.3 | 17 | 7.4 |

2 | 2 | 0.9 | 35 | 15.2 | 9 | 3 | 26 | 11.3 |

3 | 4 | 1.7 | 60 | 26 | 47 | 20.3 | 25 | 10.8 |

4 | 26 | 11.3 | 48 | 20.8 | 67 | 29 | 62 | 26.8 |

5 | 194 | 84 | 38 | 16.5 | 98 | 42.4 | 100 | 43.3 |

rank | Top Box | Top Box 2 | mean ` | median | std.dev | sampling error | ||

1 | fitness | 5(84%) | 4(11.3) | 4.74 | 5 | 0.735 | 0.094785 | |

2 | enjoy | 5(42.4%) | 4(29%) | 4.01 | 4 | 1.085 | 0.13992 | |

3 | medical | 5(43.3%) | 4(26.8%) | 3.9 | 4 | 1.311 | 0.169065 | |

4 | Social | 3(26%*) | 1(21.2%) | 2.97 | 3 | 1.383 | 0.17835 |

- The lower part of the table in 2 presents the top two box, the top two boxes for fitness is response 5 which constitutes 84% and response 4 (11.3%). For social the top two boxes are 3 (26%) and 1(21.2%).moreover, for enjoying the top box is 5(42.4%) and 4 (29%). Similarly for medical, the top box is 5(43%) and 4 (26%)
- the lower part of table 2 also presents the mean, median, and standard deviation for the variables. For fitness the average is 4.74, the deviation from the mean is 0.735 while the median is 5. For social, the average is 2.97, the deviation from the mean is 1.383 while the median is 3. For enjoyment, the average is 4.01, the deviation from the mean is 1.085 while the median is 4 and finally for medical, the average is 3.9, the deviation from the mean is 1.311 while the median is 4.

**Gretl experts**calculate the sampling error as:

5

pair | mean difference | std.err | t | Df | p |

fitness- social | 1.766 | 1.419 | 18.913 | 230 | 0.000 |

fitness- enjoy | 0.727 | 1.138 | 9.614 | 230 | 0.000 |

fitness-medical | 0.844 | 1.329 | 9.652 | 230 | 0.000 |

social-enjoy | -1.309 | 1.458 | -10.834 | 230 | 0.000 |

social-medical | -0.922 | 1.738 | -8.064 | 230 | 0.000 |

enjoy-medical | 0.117 | 1.618 | 1.098 | 230 | 0.273 |

**online Gretl tutors**there exits significant difference between fitness and social (t(230)=18.913,p=0.000<0.05), fitness and enjoy (t(230)=9.614,p=0.000<0.05), fitness and medical (t(230)=9.652,p=0.000<0.05), social and enjoy (t(230)=-10.834,p=0.000<0.05), social and medical (t(230)=-8.064,p=0.000<0.05). However, there is no significant difference in mean of (t(230)=1.098,p=0.273>0.05). 7

mean difference | std.err | t | df | p | |

Visits | 1.519 | 0.505 | 3.009 | 230 | 0.003 |

doctor recommend | |||||

NO | YES | Total | |||

utilized pool therapy | NO | Count | 107 | 20 | 127 |

% within pool | 84.30% | 15.70% | 100.00% | ||

% within doctor | 60.50% | 37.00% | 55.00% | ||

YES | Count | 70 | 34 | 104 | |

% within pool | 67.30% | 32.70% | 100.00% | ||

% within doctor | 39.50% | 63.00% | 45.00% | ||

Total | Count | 177 | 54 | 231 | |

% within pool | 76.60% | 23.40% | 100.00% | ||

% within doctor | 100.00% | 100.00% | 100.00% | ||

value | df | P | |||

Pearson ci-square | 9.165 | 1 | 0.02 | ||

Phi | 0.19 | 0.02 |

- 45% utilize therapy pool while 55%do does not utilize therapy pool
- 67.30% of those who used the therapy pool is not recommended by a doctor
- 63% of those recommended by a doctor utilized the therapy pool
- thePearson chi-square shows that there exists a significant association between the pool and doctor recommendation as chi2(1)=9.165 and p=0.02<0.05
- The phi-value tests the strength of the association between variables. The phi value is 0.19 which is a weak association. Therefore, the association between utilizing therapy pool and government recommendation is weak

mean | std error | t | df | p | |

employed | 7.53 | 0.854 | |||

retired | 10.2 | 0.604 | |||

difference | -2.678 | 1.147 | -2.335 | 229 | 0.02 |

fitness | social | enjoy | medical | |

Fitness | 1 | 0.230** | 0.229** | 0.217** |

Social | 0.230** | 1 | 0.323** | 0.196** |

Enjoy | 0.229** | 0.323** | 1 | 0.138* |

Medical | 0.217** | 0.196** | 0.138* | 1 |

correlation is significant at 0.01 level (2-tailed) | ||||

correlation is significant at 0.05 level (2-tailed) |

**Analysis of variance **

fitness | social | enjoy | medical | |||||||

fitness | 4.74 (0.74) | 0.230** | 0.229** | 0.217** | ||||||

social | 0.230** | 2.97(1.38) | 0.323** | 0.196** | ||||||

enjoy | 0.229** | 0.323** | 4.01(1.08) | 0.138* | ||||||

medical | 0.217** | 0.196** | 0.138* | 3.90(1.31) | ||||||

standard deviations in parenthesis | ||||||||||

**Correlation is significant at 0.01 level (2-tailed) | ||||||||||

*Correlation is significant at 0.05 level (2-tailed) 16 | ||||||||||

ANOVA |
||||||||||

Model | Sum of Squares | df | Mean Square | F | Sig. | |||||

Regression | 538827.3 | 5 | 107765.5 | 4.156 | .001 | |||||

Residual | 5834695 | 225 | 25931.98 | |||||||

Total | 6373522 | 230 | ||||||||

Model | R | R Square | Adjusted R Square | Std. The error of the Estimate |

0.291 | 0.085 | 0.064 | 161.0341 |

^{2}) is 0.085 and 0.064 after adjustment. This implies that the independent variables in the model account for only 6.4% of the variation in the dependent variable.

**Sample tests conducted by our Gretl assignment helpers**

Coefficients | estimates | Std. Error | t | Sig. |

(Constant) | 165.529 | 81.689 | 2.026 | 0.044 |

fitness | 12.66 | 16.575 | 0.764 | 0.446 |

social | 30.617 | 8.308 | 3.685 | 0.000 |

enjoy | -28.059 | 10.685 | -2.626 | 0.009 |

medical | 3.958 | 8.496 | 0.466 | 0.642 |

recom | 6.699 | 8.106 | 0.826 | 0.409 |

**Gretl assignment helpers**determine the significance of the coefficient by comparing their respective p-value with the level of significance. If the p-value less than the significance level, the variable is significant otherwise, the variable is not significant. Looking at the result, fitness is not statistically significant p=0.46>0.05 as well as medical, p=0.42>0.05, the same goes to recom, p=0.409>0.05. however, social is statistically significant as p=0.000<0.05. Moreover, those that view social as the importance of attending AFC adds to revenue $30.62 more than others. In the same vein, enjoyment is also statistically significant as p=0.009<0.05. Respondents that view enjoyments as the importance of attending AFC on average a $30.62 less than others. 19 According to our

**Gretl assignment help experts,**changing the level of significance to 0.01 does not affect the significance of the result 20 The recommendations are as follows:

- The management should target the retired people as they visit more often than the employed people
- Management should liaise more with doctors as 65% of those recommended by doctors utilize the therapy pool. This is to increase revenue.
- Those who view social as important for attending AFC have a revenue premium over others. Therefore, revenue can be increased by targeting more of people who have this view.
- Those who view enjoyment as important for attending AFC have a revenue deficit over others. Therefore, revenue can be increased by targeting less of people who have this view

ANOVA^{a} |
||||||

Model | Sum of Squares | df | Mean Square | F | Sig. | |

1 | Regression | 538827.294 | 5 | 107765.459 | 4.156 | .001^{b} |

Residual | 5834695.137 | 225 | 25931.978 | |||

Total | 6373522.431 | 230 | ||||

a. Dependent Variable: revenue | ||||||

b. Predictors: (Constant), recom, medical, social, enjoy, fitness |